x^2+2x/3=1/3

Solution for x^2+2x/3=1/3 equation:

x^2+2x/3=1/3

We move all terms to the left:

x^2+2x/3-(1/3)=0

We add all the numbers together, and all the variables

x^2+2x/3-(+1/3)=0

We get rid of parentheses

x^2+2x/3-1/3=0

We multiply all the terms by the denominator


x^2*3+2x-1=0

Wy multiply elements

3x^2+2x-1=0

a = 3; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·3·(-1)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*3}=\frac{2}{6}
=1/3
$